Question

How many times does the following loop execute and why?

for (unsigned m = 5; --m >= 0; )

printf(“hello\n”);

Answer 1

it will run infinite time. beacuse the condition -- m>= 0 is always true . it is always true beacuse m is unsigned and it always return +ve value. .

4 byte unsigned value ranges from 0 to 4294967295

that means

unsigned 2 =2

unsigned 1 =1

unsigned 0 =0

unsigned -1 = 4294967295

unsigned -2 =4294967294

unsigned -3=4294967293

proof: -