Question

Write a program to solve the classic FizzBuzz problem. The program should output integers 1 thru 100, one to a line.However, if the number is divisible by 3 it should output Fizz instead of the number; if the number is divisible by 5 it should output Buzz instead of the number and if it is divisible by both 3 and 5, it should output Fizz Buzz instead. write in C

Answer 1

Code is:

#include <stdio.h>

int main()

{

int i=0;

//Looping from 1 to 100

for(i=1;i<=100;i++)

{

//checking if number divisible by 5 and 3

if (i%15==0)

{

printf("Fizzbuzz");

}

//checking for number divisible by 5

else if (i%5==0)

{

printf("Buzz");

}

//checking for number divisible by 4

else if (i%3==0)

{

printf("Fizz");

}

//printing the number

else

{

printf("%d",i);

}

printf("\n");

}

return 0;

}

Output: