Question

1. Name the script args.sh.
2. The script will take any number of command line arguments.
3. The script will print (echo) each of the command line arguments on its own line, and will then print the total number of arguments entered.
4. You should use the special shell variables. One special variable contains all the command line arguments. There is another one that contains the number of command one arguments entered.
5. This script is most easily completed with a for loop, although the task can also be accomplished with a while loop, but you definitely need some type of loop since it has to process an unknown number of command line arguments.

For linux. I have not done anything on this. I am in a basic admin linux class so the commands should be simplistic in nature.

Answer 1

the script which accepts any no. of arguments and prints them, and total no. of arguments.

in script added below $* is a special shell variable, it gives token to any no. of argument.

$# is another special shell variable that gives the number of arguments passed.

create a args.sh file using any editor (nano, vi), write the following script, and save the file.

for the file to be executable, use command

chmod +x args.sh

#!/bin/sh
for Token in $*
do 
   echo $Token
done
echo $#

Screenshots :