Question

The following are the %l2 register values, the %l3 register values, and the commands to execute: After executing the command, write the values of the Condition code Z, N, V, C, and %l4 registers in the table.

1)

%l2: 0x8000_0000

%l3: 0x8000_0000

addcc %l2, %l3, %l4

-------------------------> Z=? , N=? , V=? , C=? , %l4=?

2)

%l2: 0x0123_4567

%l3: 0xFEDC_BA98

xorcc %l2, %l3, %l4

-------------------------> Z=? , N=? , V=? , C=? , %l4=?

Answer 1

Greetings!!

1)

%l2: 0x8000_0000

%l3: 0x8000_0000

-------------------------

%I4 0x1 0000 0000

Z=1 Since the 8 digit(or 32 bit) answer is 0

N=0 SInce the MSB is 0 becuase MSB reperesents sign

V=1 SInce an overflow occured

C=1 Since a carry is generated out of MSB

%l4=0000 0000 with C=1

2) xorcc %l2, %l3, %l4

%l2: 0x0123_4567

%l3: 0xFEDC_BA98

-------------------------

%I4 0xFFFF FFFF

Z=0 Since the answer is non zero  

N=1 Since the MSB is 1 which represents sign

V=0 By default

C=0 By default

%l4=0xFFFF FFFF

Hope this helps