Question

1- Write a program to print only the even numbers from 100 to 200

2- Write a program to print the odd numbers from 22 – 99

3- Write a program to calculate howe many even number from 10 to 120

1- Write a program to find only the even numbers for 12 different numbers

2- Write a program to find the odd numbers for 10 different numbers

3- Write a program to calculate howe many even number and how many odd number among 12 different numbers.

C program

Answer 1

Please find below the C programs for the given problems:

Screenshot is added for understanding the indentation along with a sample output of the porgam. Kindly comment in case of any query.

1. Program to print even numbers from 100 to 200:

PROGRAM: Please find below the commented c program to the problem:

#include <stdio.h>

int main()

{

    int number; //integer number

    printf("Below are the even numbers between 100 to 200(inclusive)\n");

    for( number = 100; number <= 200; number ++){//repeat for all numbers between 100 to 200 (including 200)

        if(number%2==0){//if current value of number is even

            printf("%d\t", number);//print the number

        }//end if

    }//end for

    return 0;

}

Screenshot:

Output:

2. Program to print odd numbers from 22-99

PROGRAM:

#include <stdio.h>

int main()

{

    int number; //integer number

    printf("Below are the odd numbers between 22 to 99:\n");

    for( number = 22; number <= 99; number ++){//repeat for all numbers between 22 to 99

        if(number%2!=0){//if current value of number is not even

            printf("%d\t", number);//print the number

        }//end if

    }//end for

    return 0;

}

Screenshot:

Output:

3. Program to count even numbers from 10 to 120:

PROGRAM:

#include <stdio.h>

int main()

{

    int number; //integer number

    int totalEven=0;//set total count of even numbers between 10 to 120 is 0

    for( number = 10; number <= 120; number ++){//repeat for all numbers between 10 to 120

        if(number%2==0){//if current value of number is even

            totalEven++;//increment the count of total even numbers

        }//end if

    }//end for

    printf("Total Even numbers between 10 to 120 are: %d", totalEven);

    return 0;

}

Screenshot:

Output:

1. Find even numbers from 12 different numbers:

Logic: The program will ask user to enter 12 numbers and find the even numbers from the entered numbers.

PROGRAM:

#include <stdio.h>

int main()

{

    int number[12]; //integer number array to hold 12 integers

    printf("Enter 12 numbers: ");

    for( int i = 0; i <12; i++){//read 12 numbers from user

         scanf("%d", &number[i]);

    }

    printf("\nBelow are the even numbers among 12 numbers: \n");

    for( int i = 0; i <12; i++){//read 12 numbers from user

        if(number[i]%2==0){//if current value of number is even

            printf("%d\t", number[i]);//print the even number

        }//end if

    }//end for

    return 0;

}

Screenshot:

Output:

2. Program to print odd numbers for 10 different numbers

Logic: The program will ask user to enter 10 numbers and print the odd numbers from the entered numbers.

PROGRAM:

#include <stdio.h>

int main()

{

    int number[10]; //integer number array to hold 10 integers

    printf("Enter 10 numbers: ");

    for( int i = 0; i <10; i++){//read 10 numbers from user

         scanf("%d", &number[i]);

    }

    printf("\nBelow are the odd numbers in 10 entered numbers: \n");

    for( int i = 0; i <10; i++){//read 12 numbers from user

        if(number[i]%2!=0){//if current value of number is not even

            printf("%d\t", number[i]);//print the odd number

        }//end if

    }//end for

    return 0;

}

Screenshot:

Output:

3. Program to count even numbers from 10 to 120:

Logic: Program will ask user to enter 12 numbers at run time and then count even and odd numbers.

PROGRAM:

#include <stdio.h>

int main()

{

    int number[12]; //integer number array to hold 12 integers

    int evenCount = 0, oddCount = 0; //set total even and odds as 0 initially

    printf("Enter 12 numbers: ");

    for( int i = 0; i <12; i++){//read 12 numbers from user

         scanf("%d", &number[i]);

    }

    for( int i = 0; i <12; i++){//read 12 numbers from user

        if(number[i]%2==0){//if current value of number is even

            evenCount++;//increment the count of even numbers

        }//end if

        else{

            oddCount++;//increment the count for odd

        }//end else

    }//end for

    printf("\nTotal Even numbers: %d", evenCount);

    printf("\nTotal Odd numbers: %d", oddCount);

    return 0;

}

Screenshot:

Output: