Question

Suppose a disk drive in your system has a rotation speed of 7,200 rpm and seek times of 1.2 ms track-to-track, or 18.5 ms full ‘stroke’ (inner edge to outer edge).

(a) What is the average latency to access this drive?

(b) If the sustained read rate is 52.4 Mbits/sec, how much more time after the average latency (you calculated above) will it take to read 250 Kbytes (assuming all those bytes are in sequential sectors on the same track)? How long to write that same amount of data if the sustained write speed is 27.5 Mbits/sec?

Answer 1

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