Question

PLEASE COMMENT CODE AND TEST THAT IT WORKS:

Write a assembly program to find the largest item in an array and store it in a AX.

Hint: Use both Jump and loop instruction to write the program.

logic:

Assume that the first item of the array is the minimum and store it in AX

Write a loop. Inside the loop, compare the each array item with the AX

If the array item is less than the AX, update AX with that variable

USE THIS CODE TO START:

.386

.model flat,stdcall

.stack4096

ExitProcess proto,dwExitCode:dword

.data

Array WORD 10, 2, 23, 45, 21, 11

MINIMUM WORD ?

.code

"insert code here"

invoke ExitProcess,0

main endp

end main

Answer 1

// The code given below provides the min and max, both elements in the array...

// Assembly language program to read an array of numbers and find the minimal and maximal elements.

DATA SEGMENT

ARR DB 10, 2, 23, 45, 21, 11

LEN DW $-ARR

MIN DB?

MAX DB?

DATA ENDS

CODE SEGMENT

ASSUME DS:DATA CS:CODE

START:

MOV AX,DATA

MOV DS,AX

LEA SI,ARR

MOV AL,ARR[SI]

MOV MIN,AL

MOV MAX,AL

MOV CX,LEN

REPEAT:

MOV AL,ARR[SI]

CMP MIN,AL

JL CHECKMAX

MOV MIN,AL

CHECKMAX:

CMP MAX,AL

JG DONE

MOV MAX,AL

DONE:

INC SI

LOOP REPEAT

MOV AH,4CH

INT 21H

CODE ENDS

END START