Question

p → q, r → s ⊢ p ∨ r → q ∨ s Solve using...

p → q, r → s ⊢ p ∨ r → q ∨ s

Solve using natural deduction rules.

Homework Answers

Answer #1

Hi, hope you are doing good.

This conclusion is true/tautology. For explanation refer the image.

Note: If you have any query please let me know in the comment. Have a nice day!

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Prove: (p ∧ ¬r → q) and p → (q ∨ r) are biconditional using natural...
Prove: (p ∧ ¬r → q) and p → (q ∨ r) are biconditional using natural deduction NOT TRUTH TABLE
Given: (P & ~ R) > (~R & Q), Q> ~P Derive: P > R. use...
Given: (P & ~ R) > (~R & Q), Q> ~P Derive: P > R. use propositional logic and natural derivation rules.
Using rules of inference prove. (P -> R) -> ( (Q -> R) -> ((P v...
Using rules of inference prove. (P -> R) -> ( (Q -> R) -> ((P v Q) -> R) ) Justify each step using rules of inference.
What is the correct meaning of the logical expression p→q∨r∧s ? ((p→q)∨r)∧s p→((q∨r)∧s) (p→(q∨r))∧s p→(q∨(r∧s))
What is the correct meaning of the logical expression p→q∨r∧s ? ((p→q)∨r)∧s p→((q∨r)∧s) (p→(q∨r))∧s p→(q∨(r∧s))
Proposition: If P⟹Q and Q⟹R are theorems, then P⟹R is also a theorem. (not using a...
Proposition: If P⟹Q and Q⟹R are theorems, then P⟹R is also a theorem. (not using a truth table only using rules 1-4, theorem 1 and axioms 1-4) Hilbert system
Prove a)p→q, r→s⊢p∨r→q∨s b)(p ∨ (q → p)) ∧ q ⊢ p
Prove a)p→q, r→s⊢p∨r→q∨s b)(p ∨ (q → p)) ∧ q ⊢ p
[16pt] Which of the following formulas are semantically equivalent to p → (q ∨ r): For...
[16pt] Which of the following formulas are semantically equivalent to p → (q ∨ r): For each formula from the following (denoted by X) that is equivalent to p → (q ∨ r), prove the validity of X « p → (q ∨ r) using natural deduction. For each formula that is not equivalent to p → (q ∨ r), draw its truth table and clearly mark the entries that result in the inequivalence. Assume the binding priority used in...
Give direct and indirect proofs of: a. p → (q → r), ¬s ∨ p, q...
Give direct and indirect proofs of: a. p → (q → r), ¬s ∨ p, q ⇒ s → r. b. p → q, q → r, ¬(p ∧ r), p ∨ r ⇒ r
Are the statement forms P∨((Q∧R)∨ S) and ¬((¬ P)∧(¬(Q∧ R)∧ (¬ S))) logically equivalent? I found...
Are the statement forms P∨((Q∧R)∨ S) and ¬((¬ P)∧(¬(Q∧ R)∧ (¬ S))) logically equivalent? I found that they were not logically equivalent but wanted to check. Also, does the negation outside the parenthesis on the second statement form cancel out with the negation in front of P and in front of (Q∧ R)∧ (¬ S)) ?
Prove: ~p v q |- p -> q by natural deduction
Prove: ~p v q |- p -> q by natural deduction
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT