Question

C++, Write an iterative routine that will have a queue and a loop to flip 2 coins: 0 for tails and 1 for heads. Add the values of the tosses of the two coins and put them onto the queue. Then dequeue the values one at a time and sum all the values. After the queue is empty, and print out the number of heads. Assume srand has already been done.

Answer 1

OUTPUT:

CODE:

#include <queue>
#include <ctime>
#include <iostream>

using namespace std;

int getHeads()
{
   srand(time(0));
   queue<int> q;
  
   for(int i = 0;i < 4;++i)
   {
       int coinTossFirstCoin = rand() % 2;
       int coinTossSecondCoin = rand() % 2;

       q.push(coinTossFirstCoin);
       q.push(coinTossSecondCoin);
   }

   int sum = 0;

   while (!q.empty())
   {
       sum += q.front();
       q.pop();
   }

   return sum;
}

int main()
{
   cout<<"Heads : "<< getHeads();
}