Question

Given the network   10.10.40.0   255.255.252.0           (note that this problem is subnetting the third octet) a....

Given the network   10.10.40.0   255.255.252.0

          (note that this problem is subnetting the third octet)

a. What is the first valid host address?

b. What is the last valid host address?

c. What is the broadcast address?

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Homework Answers

Answer #1 
Address:   10.10.40.0            00001010.00001010.00101000.00000000
Netmask:   255.255.252.0 = 22    11111111.11111111.11111100.00000000
Wildcard:  0.0.3.255             00000000.00000000.00000011.11111111
Class A
Network:   10.10.40.0/22         00001010.00001010.00101000.00000000
Broadcast: 10.10.43.255          00001010.00001010.00101011.11111111
HostMin:   10.10.40.1            00001010.00001010.00101000.00000001
HostMax:   10.10.43.254          00001010.00001010.00101011.11111110
Hosts/Net: 1022

a. What is the first valid host address?
10.10.40.1

b. What is the last valid host address?
10.10.43.254

c. What is the broadcast address?
10.10.43.255
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