Question

Implement the Calculator code, this's C++

/* Implement a calculator
take the input for a character
if character is "+", then it's going to take the input of two numbers and show the sum
if character is "-", then it's going to take the input of two numbers and show the minus result
if character is "*", then it's going to take the input of two numbers and show the product
if character is "/", then it's going to take the input of two numbers and show the divide result
if character is "%", then it's going to take the input of two numbers and show the modulus result
if character is "^", then it's going to take the input of two numbers and show the number1^number2

*/

#include <iostream>
#include <cmath>
using namespace std;
int main(){
char operation;
int number1, number2;
cout << "Enter +, -, *, /, %, ^";
cin >> operation;
if ( operation == '+' ){
//take the input of two numbers and display the sum
cout << "Enter two numbers";
cin >> number1 >> number2;
cout << "Sum is = "<< (number1+number2)<<endl;
}
else if ( operation == '-' ){
//take the input of two numbers and display the minus result
cout << "Enter two numbers";
cin >> number1 >> number2;
cout << "Number 2 subtracted from number 1 is = "<< (number1-number2)<<endl;
}
else if ( operation == '*' ){
//take the input of two numbers and display the sum
cout << "Enter two numbers";
cin >> number1 >> number2;
cout << "Product is = "<< (number1*number2)<<endl;
}
else if ( operation == '/' ){
//take the input of two numbers and display the divide result
cout << "Enter two numbers";
cin >> number1 >> number2;
cout << "Number1 divided by number 2 is = "<< (number1/number2)<<endl;
}
else if ( operation == '%' ){
//take the input of two numbers and display the modulus
cout << "Enter two numbers";
cin >> number1 >> number2;
cout << "Modulus is = "<< (number1%number2)<<endl;
}
else if ( operation == '^' ){
//take the input of two numbers and display the pow
cout << "Enter two numbers";
cin >> number1 >> number2;
cout << "Number1 raised to number2 is = "<< (pow(number1,number2))<<endl;
}
else
cout << "Invalid operator";



}

Answer 1

*******************Summary********************

The program is given below with changes and comments and output

Now the program asks repeatedly for the next operation......with exiting message..And i have done some changes to tje existing code to make it easier...

The explanation for changes is provided in comments..

I hope it works for you :) !!!!!!!!!!!

*******************Program***********************

#include <iostream>
#include <cmath>    //required forusing pow() function 
using namespace std;

int main()
{
  char operation;    //varable for storing type of operation
  int number1, number2;    //variables for storinf numbers on which
  // operation is going to be performed
  
  while(1)    //loop for asking for operation again
  {
    cout << "\nEnter +, -, *, /, %, ^ (0 for exit) : ";
    cin >> operation;    //take input for type of operation

    switch(operation)    //match operation value with cases 
    //and execute respective case
    {
      case '+':    //if operation is + then do follwing
        //take the input of two numbers and display the sum
          cout << "Enter two numbers\n";
          cin >> number1 >> number2;
          cout << "Sum is = "<< (number1+number2)<<endl;
        break;      //break out of switch case
        
      case '-':    //if operation is -
        //take the input of two numbers and display the minus result
          cout << "Enter two numbers \n";
          cin >> number1 >> number2;
          cout << "Number 2 subtracted from number 1 is = "<< (number1-number2)<<endl;
        break;      //break out of switch case
        
      case '*':    //if operation is *
         //take the input of two numbers and display the sum
          cout << "Enter two numbers \n";
          cin >> number1 >> number2;
          cout << "Product is = "<< (number1*number2)<<endl;
         break;      //break out of switch case
         
      case '/':    //if operation is /
          //take the input of two numbers and display the divide result
            cout << "Enter two numbers \n";
            cin >> number1 >> number2;
            cout << "Number1 divided by number 2 is = "<< (number1/number2)<<endl;
          break;      //break out of switch case
          
      case '%':    //if operation is %
          //take the input of two numbers and display the modulus
            cout << "Enter two numbers \n";
            cin >> number1 >> number2;
            cout << "Modulus is = "<< (number1%number2)<<endl;
          break;      //break out of switch case
          
      case '^':    //if operation is ^
          //take the input of two numbers and display the pow
            cout << "Enter two numbers\n";
            cin >> number1 >> number2;
            cout << "Number1 raised to number2 is = "<< (pow(number1,number2))<<endl;
          break;      //break out of switch case
          
      case '0':
            cout<<"Goodbye :)";    //if user wants to exit
          exit(0);      //exit the program with return 0
          
      default:    //if operation does not match any cases then
            cout << "Invalid operator";
          break;      //break out of switch case
    }//end of switch case
    
  }//end of while loop
  
}

*******************Output*************************