Question

Pointer Rewrite:

The following function uses reference variables as parameters. Rewrite the function so it uses pointers instead of reference variables, then demonstrate the function in a complete program.

int doSomething(int &x, int &y)

{

     int temp = x;

     x = y * 10;

     y = temp * 10;

     return x + y;

}

Answer 1

check out the solution.

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CODE:

#include<stdio.h>

// rewriting the function using pointers
int doSomething(int *x, int *y)
{
// declare a pointer
int *temp;

temp = x; // assign address of x to temp so now temp is pointing to x value
*x = *y * 10; // now x = 20*10 = 200 -> x points to 200 value
*y = *temp * 10; // as temp points to x value so 'temp = 200' => y = 200*10 = 2000

// return the result using pointers
return *x + *y; // x = 200 and y = 2000 => returns 200+2000 = 2200.
}

int main()
{
// variables declaration
int a, b, result;
// variable assignment
a = 10;
b = 20;
  
// function call by passing the variable references
result = doSomething(&a, &b);
  
// print the returned result
printf("Result = %d", result);
}

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OUTPUT :

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