Question

how can i convert the while loop into a for loop?

string input;

    cin >> input;

    cout << endl;

    int count = 0;

    int size = input.size();

if(input.size() == 6) {

        while(size > 0) {

            if(count < 3) {

                if((input.at(count) >= 'A' && input.at(count) <= 'Z') || (input.at(count) >= 'a' && input.at(count) <= 'z')) {

                    count++;

                }

                else {

                    cout << "error: letter expected at position " << count + 1;

                    return 0;

                }

            }

            else if(input.at(count) >= '0' && input.at(count) <= '9') {

                count++;

            }

            else {

                cout << "error: digit expected at position " << count + 1;

                return 0 ;

            }

            size--;

        }

    }

Answer 1

CODE

string input;

cin >> input;

cout << endl;

int count = 0;

int size = input.size();

if(input.size() == 6) {

for (int i=size; i > 0; i--) {

if(count < 3) {

if((input.at(count) >= 'A' && input.at(count) <= 'Z') || (input.at(count) >= 'a' && input.at(count) <= 'z')) {

count++;

}

else {

cout << "error: letter expected at position " << count + 1;

return 0;

}

}

else if(input.at(count) >= '0' && input.at(count) <= '9') {

count++;

}

else {

cout << "error: digit expected at position " << count + 1;

return 0 ;

}

}

}

}