. Solve Problem 14.18 at the end of Chapter 14 (p.466). A copy of this problem is given here for your convenience: Given a company with six individual departments and each department having ten computers or networked devices, what mask could be applied to the company net- work to provide the subnetting necessary to divide up the network equally?
given 6 departments and 10 computers in each department.
no of bits required to represent 6 departments = 3 bits
no of bits required to represent 10 computers = 4 bits
since ip consists of network and host bits.
so our network bits are (32-3-4)= 25 bits.
subnet bits= 3
host bits= 4
mask covers both network and subnet so the first 25+3 =28 bits are for mask
11111111.11111111.11111111.11110000 is the subnet mask (255.255.255.240) which allows 6 departments which allows 10 computers.
additional information:
with 4 bits total 24-2 hosts are possible that is (16-2) = 14
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