Question

In Java program:

Write a program that takes a character from the user and classifies it as a number (‘1’,’2’, ‘3’,4, 5, 6, 7  …), a letter from the alphabet (‘A’, ‘a’, ‘B’, ‘b’, …, ‘Z’, ‘z’), an arithmetic operator (‘+’, ‘-‘, ‘/’, ‘*’, ‘%’), a comparison operator (‘<’, ‘>’, ‘=’), punctuation (‘!’, ‘?’, ‘,’, ‘,’, ‘:’, ‘;’), and all other characters as a Special Character, and informs the user of the same.

If the user entered the character A, the system should say: “You entered a letter!”

If the user entered the character (, the system should say: “You entered a special character!”

Answer 1

//CharacterClassifier.java
import java.util.Scanner;
public class CharacterClassifier {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter a character: ");
        char ch = scanner.next().charAt(0);
        if(ch>='0' && ch<='9'){
            System.out.println("You entered a number!");
        }
        else if((ch>='A' && ch<='Z') || (ch>='a' && ch<='z')){
            System.out.println("You entered a letter!");
        }
        else if(ch=='+' || ch=='-' || ch=='/' || ch=='*' || ch=='%'){
            System.out.println("You entered an arithmetic operator!");
        }
        else if(ch=='<' || ch=='>' || ch=='='){
            System.out.println("You entered a comparison operator!");
        }
        else if(ch=='!' || ch=='?' || ch==',' || ch==':' || ch==';'){
            System.out.println("You entered a punctuation !");
        }
        else{
            System.out.println("You entered a special character!");
        }
    }
}

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