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For IP address of an incoming packet 192.228.19.59 and a mask in dotted decimal 255.255.255.240, what...

For IP address of an incoming packet 192.228.19.59 and a mask in dotted decimal 255.255.255.240, what is the IP host number in this subnet that the IP packet is headed to? Please show your work.

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Answer #1

For obtaining subnet id of the subnet, AND operation is applied on IP address and mask.

Binary representation of IP address 192.228.19.59 is 11000000.11100100.00010011.00111011.

Binary representation of subnet mask 255.255.255.240 is 11111111.11111111.11111111.11110000.

Fron Subnet mask it can be concluded that first 28 bits are representing subnet id and last 4 bits are representing host id.

Subnet ID is 192.228.19.48, and last 4 bits of the IP address(11000000.11100100.00010011.00111011) which represents host are 1011 which is 11.

Answer: Host Number to which IP packet is headed is 11.

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