Question

****please don't copy and paste and don't use handwriting

Q3:

Write LMC assembly code that prints the minimum of two numbers.

HINT: use and extend the table below for your solution.

Mailbox	Mnemonic	Code	Instruction description

Q4:

Convert the given exponential expression into SEEMMMMM floating-point format (use excess-50 notation to represent an exponent) and perform multiplication operation,  

0.85067 x 10²

0.52099 x 10^-1

Answer 1

Q3. Table not provided, please provide table.

Q4.

1) 0.85067×10²

The number is positive, hence sign of mantissa is positive.

So, first digit S=0

The exponent value is 2.

So, the Excess-50 value is represented by 52 (which was got from 50+2).

EE= 52 (second and third digit).

Mantissa = 85067 (last 5 digits)

Thus, 0.85067×10²

represented in SEEMMMMM format is

05285067

2)

2) 0.52099×10^-1

The sign of mantissa is positive(+ve).

So, S=0(first digit).

The exponent value is -1.

So, the Excess-50 value is represented by 49.(which was got from 50-1).

So, EE= 49 (second and third digit).

The mantissa value is 52099

So, M= 52099 (last 5 digits).

Thus, 0.52099×10^-1

represented in SEEMMMMM format is

04952099