Question

I am attempting to cause a simple stack buffer overflow in the C language. This is the code I have:

#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[]){
char buffer[10];
strcpy(buffer,argv[1]);
};

When I run this code I use the input "0123456789" a total of 10 bytes and I recieve an error that the core was dumped. But I thought since I defined a buffer of size 10 any input greater than 10 would deliver that error, inputs less than 10 shouldn't.

I tried putting in "12345678" and this was fine so it seems like the buffer flow error occurs after 8 bytes even though the buffer is declared to be the size of 10.

Can someone help explain to me why this is the case?

Answer 1

There is no problem in the program. It is running perfectly.

#include <stdio.h>
#include <string.h>

int main(int argc, char *argv[]){
   char buffer[10];
   strcpy(buffer,argv[1]);
  
   printf("%s\n\n", buffer);
  
   return 0;
};

OUTPUT: