Question

2) With a subnet mask 255.255.224.0, what is the CIDR for the subnet with an address...

2) With a subnet mask 255.255.224.0, what is the CIDR for the subnet with an address 210.240.10.0?

Homework Answers

Answer #1
IP Address: 210.240.10.0
----------------------------------------
Let's first convert this into binary format
210.240.10.0
Let's convert all octets to binary separately
Converting 210 to binary
Divide 210 successively by 2 until the quotient is 0
210/2 = 105, remainder is 0
105/2 = 52, remainder is 1
52/2 = 26, remainder is 0
26/2 = 13, remainder is 0
13/2 = 6, remainder is 1
6/2 = 3, remainder is 0
3/2 = 1, remainder is 1
1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11010010
210 in binary is 11010010

Converting 240 to binary
Divide 240 successively by 2 until the quotient is 0
240/2 = 120, remainder is 0
120/2 = 60, remainder is 0
60/2 = 30, remainder is 0
30/2 = 15, remainder is 0
15/2 = 7, remainder is 1
7/2 = 3, remainder is 1
3/2 = 1, remainder is 1
1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11110000
240 in binary is 11110000

Converting 10 to binary
Divide 10 successively by 2 until the quotient is 0
10/2 = 5, remainder is 0
5/2 = 2, remainder is 1
2/2 = 1, remainder is 0
1/2 = 0, remainder is 1
Read remainders from the bottom to top as 1010
10 in binary is 00001010

Converting 0 to binary
Divide 0 successively by 2 until the quotient is 0
Read remainders from the bottom to top as 
0 in binary is 00000000

===================================================================================
||    210.240.10.0 in binary notation is 11010010.11110000.00001010.00000000    ||
===================================================================================

Subnet address: 255.255.224.0
----------------------------------------
Let's convert this into binary format
255.255.224.0
Let's convert all octets to binary separately
Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
255/2 = 127, remainder is 1
127/2 = 63, remainder is 1
63/2 = 31, remainder is 1
31/2 = 15, remainder is 1
15/2 = 7, remainder is 1
7/2 = 3, remainder is 1
3/2 = 1, remainder is 1
1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
255 in binary is 11111111

Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
255/2 = 127, remainder is 1
127/2 = 63, remainder is 1
63/2 = 31, remainder is 1
31/2 = 15, remainder is 1
15/2 = 7, remainder is 1
7/2 = 3, remainder is 1
3/2 = 1, remainder is 1
1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
255 in binary is 11111111

Converting 224 to binary
Divide 224 successively by 2 until the quotient is 0
224/2 = 112, remainder is 0
112/2 = 56, remainder is 0
56/2 = 28, remainder is 0
28/2 = 14, remainder is 0
14/2 = 7, remainder is 0
7/2 = 3, remainder is 1
3/2 = 1, remainder is 1
1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11100000
224 in binary is 11100000

Converting 0 to binary
Divide 0 successively by 2 until the quotient is 0
Read remainders from the bottom to top as 
0 in binary is 00000000

====================================================================================
||    255.255.224.0 in binary notation is 11111111.11111111.11100000.00000000    ||
====================================================================================

Remove all dots to form 11111111111111111110000000000000
Remove all 0's from the right side to form 1111111111111111111
Number of 1's in this is 19
so, Subnet mask is /19

For Calculating network ID, keep first 19 bits of 11010010.11110000.00001010.00000000 and set all remaining bits to 0.
so, network ID in binary is 11010010.11110000.00000000.00000000
11010010.11110000.00000000.00000000:
----------------------------------------
11010010.11110000.00000000.00000000
Let's convert all octets to decimal separately
Converting 11010010 to decimal
=> 11010010
=> 1x2^7+1x2^6+0x2^5+1x2^4+0x2^3+0x2^2+1x2^1+0x2^0
=> 1x128+1x64+0x32+1x16+0x8+0x4+1x2+0x1
=> 128+64+0+16+0+0+2+0
=> 210
11010010 in decimal is 210

Converting 11110000 to decimal
=> 11110000
=> 1x2^7+1x2^6+1x2^5+1x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 1x128+1x64+1x32+1x16+0x8+0x4+0x2+0x1
=> 128+64+32+16+0+0+0+0
=> 240
11110000 in decimal is 240

Converting 00000000 to decimal
=> 00000000
=> 0x2^7+0x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 0x128+0x64+0x32+0x16+0x8+0x4+0x2+0x1
=> 0+0+0+0+0+0+0+0
=> 0
00000000 in decimal is 0

Converting 00000000 to decimal
=> 00000000
=> 0x2^7+0x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 0x128+0x64+0x32+0x16+0x8+0x4+0x2+0x1
=> 0+0+0+0+0+0+0+0
=> 0
00000000 in decimal is 0

===================================================================================
||    11010010.11110000.00000000.00000000 in decimal notation is 210.240.0.0    ||
===================================================================================
==========================================
||    So, Network ID is 210.240.0.0    ||
==========================================
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. Write the IP address 222.1.1.20 mask 255.255.255.192 in CIDR notation. Recall that CIDR notation uses...
1. Write the IP address 222.1.1.20 mask 255.255.255.192 in CIDR notation. Recall that CIDR notation uses the IP address in dotted decimal followed a /n, where n is the number of significant or "unmasked" bits 2. A network administrator wants to place 27 subnets on a /23 network.  How many bits would be in the host field of the address? Just enter the integer number of bits with no label.
Given the following IP address from the Class B address range using the default subnet mask:...
Given the following IP address from the Class B address range using the default subnet mask: 100.110.0.0. Your network plan requires no more than 64 hosts on a subnet. When you configure the IP address in Cisco IOS software, which value should you use as the subnet mask? a) 255.255.0.0 b) 255.255.128.0 c) 255.255.255.128 d) 255.255.255.252 If your current Network ID is 223.40.35.0 with the default subnet mask and you need to have 15 subnets and maximizing the number of...
What is the network address if given this IP address and the following subnet mask?  Please note...
What is the network address if given this IP address and the following subnet mask?  Please note that the network may be different if the subnet mask is different. IP address 178.47.188.176 255.255.255.0     network 178.47.188.0 255.255.255.240 network 178.47.188.176 255.255.0.0          network 178.47.0.0 255.255.240.0      network 178.47.176.0 How many total/useable hosts? 1a. /20    Total_______________          Useable_______________ 1b. /21    Total_______________          Useable_______________ 1c. /28    Total_______________          Useable_______________ 1d.  /27     Total_______________          Useable_______________ 1e. /30     Total_______________          Useable_______________
Given the IP address and subnet mask 214.20.1.15/255.255.255.192 (/26) Whats the subnet ip range, network ID,...
Given the IP address and subnet mask 214.20.1.15/255.255.255.192 (/26) Whats the subnet ip range, network ID, broadcast address, and number of available IPs in the subnet
Calculate the network address, broadcast address, and subnet mask for 94.35.35.146/25. Network + Guide to networks...
Calculate the network address, broadcast address, and subnet mask for 94.35.35.146/25. Network + Guide to networks seventh addition chapter 10
In a class C subnet, we know the IP address of one of the hosts and...
In a class C subnet, we know the IP address of one of the hosts and the subnet mask as given below: IP Address: 198.48.82.176 Subnet mask: 255.255.255.224 1) What is the first valid host address in the subnet? (in dotted decimal) 2) What is the last valid address in the subnet? (in dotted decimal) 3) What is the subnet network address? (in dotted decimal) 4) What is the subnet broadcast address? (in dotted decimal) 5) What is the number...
Please write down the Internet’s IP layer lookup routing algorithm in two cases (subnet mask and...
Please write down the Internet’s IP layer lookup routing algorithm in two cases (subnet mask and CIDR).
A) With the following address and subnet mask: 147.12.38.1 255.255.255.0 List the network and host parts...
A) With the following address and subnet mask: 147.12.38.1 255.255.255.0 List the network and host parts in dotted decimal format. b) Give the full address for the following IPv6 address ABCD:0012:0000:D812:0000:0000:0001. Please rewrite it in abbreviated form
Short answer: How does changing the subnet mask allow you to divide up an address space?
Short answer: How does changing the subnet mask allow you to divide up an address space?
What is the Custom Subnet Mask for the subnetted IP 204.188.89.0? NOTE: do not add the...
What is the Custom Subnet Mask for the subnetted IP 204.188.89.0? NOTE: do not add the /bits (extended prefix) to the end of your answer. Is the same Custom Subnet Mask used for each of the four subnets? Yes or no?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT