Question

Write a program that asks for five test scores. The program should calculate the average
test score and display it. The number displayed should be formatted in fixed-point notation,
with one decimal point of precision.
Display:
(1) your (1) interactive dialog with the console,
(2) the five test scores entered, and
(3) the computed average.

the pseudo code is:

you will need to include a library for the output formatting
for specifying decimal point display:
#include <iomanip> in std namespace

assume number of test scores does not change, so
declare a constant for the number of test scores:

const int N(5)

declare memory for N number of test scores:
int t1,t2, ....

get test scores from keyboard input:
cout << "Enter Test Score 1: "
cin >> t1

echo the result for visual validation:
cout << "You entered " << t1 << "

do for N test scores ...

declare variable for sum of all scores:
int sum(0)

compute sum:
sum = t1 + ....

compute average test score
----------------------
if we should perform the operation sum/N...
we will not get the correct result because
division on two interger operands, (sum & N) ,
results in a whole number -- we lose the
fraction part of the result.
we need to cast one of the operands in its
register so we can get a floating point result.
the syntax for doing this is:

double average = static_cast<double>(sum) / N;

display results

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Answer 1

SOURCE CODE

#include <iostream>
using namespace std;
int main() {
   const int N=5;
   int t1,t2,t3,t4,t5;  
   cout << "Enter Test Score 1: ";
   cin >> t1;
   cout << "Enter Test Score 2: ";
   cin >> t2;
   cout << "Enter Test Score 3: ";
   cin >> t3;
   cout << "Enter Test Score 4: ";
   cin >> t4;
   cout << "Enter Test Score 5: ";
   cin >> t5;
   cout << "\nYou entered " << t1 << " "<< t2 << " "<< t3 << " "<< t4 << " "<< t5;
float sum = 0.0;
sum = t1+t2+t3+t4+t5;   
double average = static_cast<double>(sum) / N;
cout<<"\nAverage of all array elements is "<<average;
return 0;
}

OUTPUT SCREENSHOT

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