Question

square the elements of a linear list of numbers

(square ‘(1 -3 -5 7)) => (1 9 25 49)

using DrRacket

The code has to be from scratch, no library functions. and kindly explain what each line of code is doing.

Answer 1

Here is the required code in DrRacket:

;defining a list that contains elements
(define l (list 1 -3 -5 7))

;displaying given elements
(display "Elements Given: \n")
(for ([i l])
(display i)
(display " "))

;displaying squared elements
(display "\n\nSquared Elemnts: \n")
(for ([i l])
(define x (* i i)) ;defining variable x that stores the square of ith element in list
(display x)
(display " "))

Here is the Output of the Sample List: