Question

Give the output of the program:

void thing1();

void thing2();

int main()

{

     printf("3 ");

thing1();

     printf("4");

thing(2);

     printf("5");

     return 0;

}

void thing1()

{

     printf("Gotcha!" );

}

void thing2()

{

     printf("HA! ");

}

Answer 1

Answer : Error (Linker error)

Explanation: See The program might have run even if we didn't add the header file #include<stdio.h> to use built-in function like printf and scanf.
-But it will generate Warning regarding it.
- So the program will run fine but thing(2) this function is not defined it should be either thing2() so that it would have run fine.
- So in the end the program has generated a error with undefined reference to `thing' error.

#Code

// Header is not included but the program will run with warnings.
//#include<stdio.h>

// Function declaration
void thing1();
void thing2();

int main()
{
   printf("3 ");
// Calling function thing1()  
thing1();
   printf("4");
// Calling function tinng2 which is not defined.
// Or it should be thing2()  
thing(2);
//thing2(2);
   printf("5");
   return 0;
}

// Function defination
void thing1()
{
   printf("Gotcha!");
}

void thing2()
{
   printf("HA! ");
}

#Output

#Running Code

// Header is not included but the program will run with warnings.
//#include<stdio.h>

// Function declaration
void thing1();
void thing2();

int main()
{
   printf("3 ");
// Calling function thing1()  
thing1();
   printf("4");
// Calling function tinng2 which is not defined.
// Or it should be thing2()  
//thing(2);
thing2();
   printf("5");
   return 0;
}

// Function defination
void thing1()
{
   printf("Gotcha!");
}

void thing2()
{
   printf("HA! ");
}

#Running Output

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