Simplify to reach 3 product terms each of 2 variables only. X’YZ + XYZ’ + XYZ + XY’Z
The given expression is:
X’YZ + XYZ’ + XYZ + XY’Z
The solution of above expression is given below:
= X’YZ + XYZ’ + XZ(Y + Y’)
= X’YZ + XYZ’ + XZ (By using complement law, X + X' = 1)
= X’YZ + X(YZ’ + Z)
= X’YZ + X( Z + Z’Y)
= X’YZ + X( Z + Y) (Because X + X'Y = X + Y)
= X’YZ + XZ + XY
= Z(X’Y + X) + XY
= Z(X + X’Y) + XY
= Z(X + Y) + XY (Because X + X'Y = X + Y)
= ZX + ZY + XY
= XY + ZY + ZX
= XY + YZ + ZX
This result has three product term and each of two variable only.
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