Question

# Description: This program is a function which calculates pi #per Leibniz formula,based on the number of values passed to it.

# Programmer: xxxxx

def calculate_pi(n):

    total, sign = 0, 1

    for i in range(n):

        term = 1 / (2 * i + 1)

        total += term * sign

        sign *= -1

    total *= 4

    return total

n = int(input("How many terms: "))

print(calculate_pi(n))

How many terms: 12

3.058402765927333

HW

In Puthon

Modify the program above so that it includes exception handling, is “debugged”, and allows the user to execute the program multiple times without exiting it. Be sure to correct any issues found if there is any.

Answer 1

def calculate_pi(n):
    try:
        total, sign = 0, 1
        for i in range(n):
            term = 1 / (2 * i + 1)
            total += term * sign
            sign *= -1
        total *= 4
        return total
    except Exception as e:
        print("Exception occurred..")
        return 0

choice = "yes"
while(choice=="yes"):
    n = int(input("How many terms: "))
    print(calculate_pi(n))
    choice = input("Want to run it again (yes/no)? ")