Question

##1.Write a function named shout. The function should accept a string argument

##and display it in uppercase with an exclamation mark concatenated to the end.

##

##2. Examine the following function header, then write a statement that calls

##the function, passing 12 as an argument.

##def show_value(quantity):

##3. Look at the following function header:

##def my_function(a, b, c):

##Now look at the following call to my_function:

##my_function(3, 2, 1)

##When this call executes, what value will be assigned to a? What value will be

assigned

##to b? What value will be assigned to c?

Answer 1

1)

def shout(string):
print(string.upper()+"!");
  
shout("hello")

Expected output:

2)

def show_value(quantity):
print(quantity);
  
  
show_value(12);#passing 12 as argument to show_value function

Expected output:

12

3)

def my_function(a,b,c):
print("a ="+str(a)+" b ="+str(b)+" c ="+str(c));
  
my_function(3,2,1);

Expected output:

a =3 b =2 c =1

The function header says that the values of a,b,c will be 3,2,1 because in whatever order the parameters are passed in a function call the same order will be used for assigning the variables in the function .