Question

3.  What is the bit pattern represented by the hexidecimal notation 6E?

Answer format: two 4-bit patterns. Include all leading and trailing zeros. (e.g., 1010 1010)

4.Express the following bit pattern in Hexedecimal notation: 1111 0010 1000
Answer format: for each 4-bit pattern, enter a single character. Can be either a capital letter or a digit. (e.g., AB9)

5. Suppose that a color digital photo has 512 pixels per row and 512 pixels per column,
and that each pixel requires two bytes of storage.
How many such pictures could you have in your camera if the camera had 6 GB of storage available?

Answer format: all digits; no commas. (e.g., 1234)

6.Assume that a single page of printed text requires 52 lines of text, and that each line of text averaged 80 characters.
If each character takes up two bytes of storage, how many bytes are required to hold a 500 page novel?

		4,400,000 bytes
		4,200,000 bytes
		4,600,000 bytes
		4,000,000 btyes

Answer 1

Hexadecimal     Binary
    0           0000
    1           0001
    2           0010
    3           0011
    4           0100
    5           0101
    6           0110
    7           0111
    8           1000
    9           1001
    A           1010
    B           1011
    C           1100
    D           1101
    E           1110
    F           1111

3)  0110 1110
4)  F28
5)
total number of pixels = 512*512
total number of bytes per picture = 512*512*2 = 2^9 * 2^9 * 2 = 2^19 bytes
total size of storage = 6GB = 6*2^30 bytes
number of pictures = 6*2^30 / 2^19
= 6 * 2^11
= 6 * 2048
= 12288
Answer: 12288
6)
number of bytes = 500 * 52 * 80 * 2 = 4160000
Answer: B.  4,200,000 bytes