Question

1.) In order to have a loop that adds odd values from 10 through 20, what would be entered in the blanks below:
int oddAccumulator = 0;
for (int i = [a]; i < [b]; i++)
{
if ((i % 2) != 0)
{
oddAccumulator += [c];
}
}
WriteLine("The sum of odd integers in the range of 10 - 20 is: {0} ", oddAccumulator);

*I've figured out the answer for [a] = 10, [b] = 20, but I can't figure out [c]. Please answer [c].

2.) n order to have a loop that displays the values 5 through 15 on separate lines, what would be entered in the blank below:
for (int i = 5; i < ______; i++)
{
WriteLine(i);
}

*I've put 15 and 20, which is wrong. Please answer with explanation.

Answer 1

Solution

[a]=10

[b]=20

[c]=i

Explanation

i value is initially 10 the loop will execute upto I<20

if ((i % 2) != 0)

this loop will work only for odd numbers

11,13,15,17,19

oddoddAccumulator=oddAccumulator +i;

oddAccumulator =0+11

oddAccumulator=11

so it will accumulate odd numbers one by one

Correct Code

int oddAccumulator = 0;
for (int i =10; i < 20; i++)
{
if ((i % 2) != 0)
{
oddAccumulator += i;
}
}
WriteLine("The sum of odd integers in the range of 10 - 20 is: {0} ", oddAccumulator);

--

2)

Answer

16

Explanation

for example if you put 15, it will print from 5,6,7,8...14

so 16 will be the correct answer

i<16

this will execute 15<16

Correct code

for (int i = 5; i < 16; i++)
{
WriteLine(i);
}

--

all the best

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