Question

How many address lines (bits in the address) and I/O lines (bits in the actual data) are needed for 2K X 16 word-addressable memories?

Could you show the steps on how to solve this? thank you!

Answer 1

For 2Kx16 memory,

The number of words = 2K

Number of bits per word = 16

In the 2Kx16 memory, the number of address lines is obtained number of words, which is 2K= 2^11

Therefore it requires 11 Address Lines

The number of data lines is equivalent to number of bits per word,that is 16

The I/O lines are calculated as the sum of address lines and the number of bits, that is 11+16 = 27

Therefore it requires 27   I/O lines

There exist a simple formula to calculate the number of address lines and data lines. For a memory of 2^m * n, the number of address lines is m and the number of data lines is n. Also the number of I/O lines is m+n