Question

can you show work please

What valid host range is the IP address 172.19.160.14/27 a part of?

What is the first valid host on the subnetwork that the node 172.24.192.84 255.255.255.128 belongs to?

How many subnets and hosts per subnet can you get from the network 172.25.0.0/25?

What is the first valid host on the subnetwork that the node 172.28.230.89/26 belongs to?

Which subnet does host 172.18.9.246/23 belong to?

Answer 1

What valid host range is the IP address 172.19.160.14 / 27 a part of?

ip address: 172.19.160.14 / 27

Classless inter-domain routing (CIDR) is used.

27 bits are used in network id, remaining 5 bits for host id.

lets write 172.19.160.14 / 27 in bit form

                     ( only last byte is required here) --> 172 . 19 . 160 .000 01110

                     red indicate network part

                    black indicate host part.

lets take the host part ---> 01110 ( 5 bit )

                                    ----> here 2^5 = 32 numbers possible.

                                                           = 0 to 31

so first ip = 172.19.160.0 / 27 ( network id )

second ip= 172.19.160.1 /27 (usable)

*

*

31 st IP    = 72.19.160.30 / 27(usable)

last ip     = 72.19.160.31 / 27    (broadcast ip)

valid host range= 72.19.160.1 /27 to 31 st IP    = 72.19.160.30 / 27

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What is the first valid host on the subnetwork that the node 172.24.192.84 ,255.255.255.128 belongs to?

ip address =172.24.192.84

mask          =255.255.255.128

network id = ip address AND mask

172.24. 192 .01010100 + ( only last byte is converted to bit beacuse x AND 255 give x itself )

255.255.255. 10000000

172 . 24 .192 . 0000000

-> network id = 172 . 24 .192 . 0000000

                       =172 . 24 .192 .0

->first usable ip = 172 . 24 .192 . 1

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How many subnets and hosts per subnet can you get from the network 172.25.0.0/25?

subnet mask is not given. so lets assume default mask is 255.255.0 . 0 ( class B)

network id= ip address AND mask = 172.25.0.0 / 16 ( only 16 bit is used )

172.25.00000000.0 0000000 / 25 ( 9 bits remaining for subnet )

9 bits for subnet: so total ( 2^9 -2 ) = 512 - 2 = 510 subnets

7 bits for host id : so tatal (2^7 -2 )= 128 -2 =126 host/subnet

( 2 substracted because 1 will be network id and one will be host id)

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What is the first valid host on the subnetwork that the node 172.28.230.89/26 belongs to?

26 bits for network id so,

172.28.230.89 = 172.28.230.01011001 ( red denote networ part, lets make the host part 0)

                        =172.28.230.01000000

                        =172.28.230.64

172.28.230.89/26 belongs to networ id 172.28.230.64/26

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Which subnet does host 172.18.9.246/23 belong to?

23 bits for network id so,

172.18.9.246= 172.18.00001001. 11110110( red denote networ part, lets make the host part 0)

                        =172.18.0000100 0.00000000

                        =172.18.8.0

172.18.9.246/23 belongs to networ id 172.18.8.0/23