Question

Consider the array of double values called "measurements". Complete the code so it would display on the console the values from "measurements" that deviate from TARGET by no more than TOLERANCE. You may want to use Math static method "abs", which returns the absolute value of a given number or expression. For example, if double variable measure = 2.9, then Math.abs(measure - 3) = 0.1..

To be clear, the expected output of your program should be the numbers 3.51, 3.49, 3.51, and 3.50.

double measurements[] = { 3.51, 3.53, 3.49, 3.51, 3.47, 3.50 };
double TOLERANCE = 0.01;
double TARGET = 3.5;

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Answer 1

Java Program:

public class Main
{
        public static void main(String[] args) {
                double measurements[] = { 3.51, 3.53, 3.49, 3.51, 3.47, 3.50 };
        double TOLERANCE = 0.01;
        double TARGET = 3.5;
        
        for (int i = 0; i < measurements.length; i++)
        {
            double tol = Math.abs(measurements[i] - TARGET);
            if (tol < TOLERANCE)
            {
                System.out.print(measurements[i] + " ");
            }
        }
        }
}

Output:

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