Question

The data types of: 47+6.5, 2*6e-2L, +'0', and sizeof(38.2) are: (Note 2.10) A. float, long, char,...

The data types of:
47+6.5, 2*6e-2L, +'0', and sizeof(38.2) are:
(Note 2.10)
A. float, long, char, unsigned int
B. int, long, char, size_t
C. double, long double, int or unsigned,
size_t
D. int, long double, int, double
E. implementation dependent

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Homework Answers

Answer #1

Solution:

  • 47 + 6.5 = 53.5---------- it is a float type of data because it contains floating data.
  • 2*6e-2L -------- because of specifier 'L' this number is long double
  • +'0' ---------- '' single quotes represent a char in the C language so this is type char.
  • sizeof(38.2) ------------- the sizeof() method returns a long unsigned int value as a result

Truly speaking none of the options are matching but most nearest option is option A - float, long, char, unsigned int instead of long it should be long double and for unsigned int it should be long unsigned int.

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