Question

C Programming:-

What is the type of the variable x?

uint8_t *x[256];

(Do not use spaces in your answer)

What type does the variable x decay to when used in an expression?

uint8_t *x[256]

(Do not use spaces in your answer)

Consider the following function whose purpose is to return an array of 3 strings that are initialized to the strings in the character arrays s1, s2, and s3:

#include <string.h>
#include <stdlib.h>

char** stringstoarray(char* s1, char* s2, char* s3) {

    // dynamically allocate space for the pointer array itself.
    char** strings = ________________________           
  

    strings[ 0 ] = strdup(s1);  // initialize first string
    strings[ 1 ] = strdup(s2);  // initialize first string
    strings[ 2 ] = strdup(s3);  // initialize third string

    return strings;

}

In order for the function for the function to carry out its purpose, fill in the blank with the necessary code.

Do not use spaces in your answer and don't forget a semi-colon at the end of your answer.

Answer 1

(i)  uint8_t is of unsigned int of length 8bits data type.

(ii) uint8_t has a result of 2^8=256. It is because 255 is the maximum value of an unsigned int or an uint8_t as the range varies from 0-255. So if we put a value of 256, our result would be 0.

(iii) char** strings = new strings *[3];

In this the strings is pointing to 3 string arrays which will further point to the data.

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