Question

For your project CPU:

                                                                52 bits

Opcode 10

General register 6

Index register 5

Mode 4

Future 2

Address 25

a) Maximum number of instruction?

b) How many general registers there are?

c) How many types of instructions there are?

d) Size of your Memory in K,M,G,T

e) Largest unsigned binary number in a word of memory?

Answer 1

a) Maximum number of Instructions = 2^10 = 100

b) Number of general registers = 6

c) Types of instructions = 3

• Data Manipulation
• Data Transfer
• Program Control

d) The nearest byte boundary after 52 bits is at 56 bits, i.e., 7 Bytes.

Maximum number of instructions = 100

Size of memory = 7*100 = 700 Bytes

= 0.7 KB

= 7 * 10^4 MB

= 7 * 10^7 GB

= 7 * 10^10 TB

e) Memory = 25 bits.

Therefore the largest unsigned binary number in a word of memory is 1111111111111111111111111₂ .