Question

Please only simple assembly language

Create a program to use ecx to count from the value in eax to the value in ebx. So, for example, if eax contains 5 and ebx contains 9, then you should have a loop in which ecx takes the values 5, 6, 7, 8, and 9. Verify that your program runs using the debugger.

Answer 1

Live Demo

section    .text

   global _start         ;must be declared for using gcc

_start:                     ;tell linker entry point

   mov eax, [num1] ;move number 5 to eax

   mov     ebx, [ num2] ;move number 9 to ebx

   mov   [count],eax ; move 9 to count space

   next:

   mov   ecx,count ; move count to ecx

   mov   edx, 2 ;print the value of ecx using the following statements

   mov   ebx,1 ;file descriptor (stdout)

   mov   eax,4 ;system call number (sys_write)

   int   0x80 ;call kernel

   inc   ecx ; increment ecx by 1

   mov   [count],ecx ;move the increment value to count

   cmp   ecx,ebx ;compare the value of ecx with ebx

   jne   next ;if ecx is not equal to ebx the goto next

   mov   eax, 1 ;exit the program

   int   80h

section    .data

      num1 dd '5'

   num2 dd '9'

   segment .bss

   count resb 2

output

5

6

7

8

9