Question

1. Given a positive integer, determine if it is a power of two. Output “yes” or “no”. For example, output yes for 32 (2^5) and no for 25.

(Hint: assume it is true with a Boolean variable then use a loop to find a value to show it is false by setting the Boolean variable to false)

C++ CODE PLEASE

Answer 1

#include<iostream>
#include<cmath>
using namespace std;
int main(){
        int n;
        cout<<"Enter integer: ";
        cin>>n;
        bool flag=0;
        // looping to find powers untii it reaches given value
        for(int i=0;;i++){
            //if it is power of 2 than make flag as true and break
                if(pow(2,i)==n){
                        flag=1;
                        break;
                }
                // if it is greater than n stop the loop
                if(pow(2,i)>n)
                        break;
        }
        if(flag)
                cout<<"True";
        else
                cout<<"False";
}

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