Question

3.21 LAB C++ Code: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is: 1712 the output is: 1712 - leap year

Ex: If the input is: 1913 the output is: 1913 - not a leap year please help!!!

Answer 1

#include <iostream>

using namespace std;

int main() {
    int inputYear;
    bool isLeapYear = false;
    cin >> inputYear;

    if (inputYear % 4 == 0) {
        if (inputYear % 100 == 0) {
            isLeapYear = inputYear % 400 == 0;
        } else {
            isLeapYear = true;
        }
    }

    if (isLeapYear) {
        cout << inputYear << " - leap year" << endl;
    } else {
        cout << inputYear << " - not a leap year" << endl;
    }
    return 0;
}