Question

(Assembly MIPS)

draw random pixels on the screen continuously. When the user presses a key, you change the color of the pixel.

You will set the Bitmap Display to the following

1. Unit Width and Height will be 8 pixels

2. Display Width and Height will be 1024

3. Base Address will be 0x10010000 (static data)

The currentColor to draw will start as Blue 0x0000FF00

Remember that the color written is 0x00RRGGBB

do {

Generate a number X between 0 and the number of rows for the display

Generate a number Y between 0 and the number of columns for the display

Write the currentColor to that location in memory.

Check to see if a Key is pressed.  

0 turns Red off, 1 turns Red on

2 turns Green off, 3 turns Green on

4 turns Blue off, 5 turns Blue on

9 exits the program

}

Part 2. For the second part of the program, modify how you monitor the Keypad.

0 Toggles Red

2 Toggles Green

3 Toggles Blue

Answer 1

For example in a 32 bit RGBA image each pixel is made up from 4 parts

red = 8 bi

green = 8 bit

blue = 8 bit

alpha = 8 bit

Each can be set to a value between 0 and 255

So you and just treat the image as an array of bytes and change each pixels color value

Image image = CreateImage(

for(int i = 0; i < image.size(); i+

image[i] = RandomNumberBetween(0, 255)

Or create the image from an array of byte

int byteArray[width * height * 4

for(int i = 0; i < width * height * 4; i+

image[i] = RandomNumberBetween(0, 255)

Image image = createImageFromByteArray(byteArray

You could also create a simple opengl scene and do it in a shader

float rand(vec2 co

return fract(sin(dot(co.xy ,vec2(12.9898,78.233))) * 43758.5453)

void main(void

gl_FragColor = rand(gl_TexCoord[0].xy)

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