Question

Write a C program that counts the number of repeated characters in a phrase entered by the user and prints them. If none of the characters are repeated, then print “No character is repeated”

For example: If the phrase is “full proof” then the output will be:

Number of characters repeated: 3

Characters repeated: f, l, o

Note: Assume the length of the string is 10.

Answer 1

/*If you any query do comment in the comment section else like the solution*/

#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main() {
    char arr[1000];
    int freq[26];
    int i;
    for(i=0;i<1000;i++)
        arr[i]='\0';
    for(i=0;i<26;i++)
        freq[i]=0;
    printf("Enter a string : ");
    gets(arr);
    printf("%s",arr);
    for(i=0;i<strlen(arr);i++)
    {
        freq[toupper(arr[i])-65]++;
    }
    int count = 0;
    for(i=0;i<26;i++)
    {
        if(freq[i] > 1) {
            count++;
        }
    }
    printf("Number of characters repeated: %d\n", count);
    printf("Characters repeated: ");
    for(i=0;i<26;i++)
    {
        if(freq[i] > 1) {
            printf("%c",(97+i));
            count--;
            if(count != 0) {
                printf(", ");
            }
        }
        
    }
}