Question

An organization has a network address of 135.102.192.0/18. The organization wants to create subnets so that each subnet can support 1000 hosts.

a. How many bits of host id are required?

b. How many bits of subnet id are there?

c. How many possible subnets can this organization have?

Answer 1

In Given IP 135.102.192.0 / 18

We have 2^32 - 18 = 2^14 = 16384 Hosts

Part A)

Number of Bits = log₂Total Host

Here Total Host = 1000

Number of Bits = upper bound(  log₂1000 ) = 10 Bits

Note : We take Upper bound because 2^9 = 512 and we need 1000 hosts . So Minimum bits needed are 10

Hence Host ID needs 10 Bits

Part B)

As network mask is Given as / 18

So We get Subnet Mask as 18 1's followed by 0's = 255 . 255 , 192 . 0

So total Bits we have 32 = Network Bits + Subnet Bits + Host Bits

32 = 18 + Subnet Bits + 10

Subnet Bits = 4

Hence Subnet ID Needs 4 bits

Part C)

As subnet ID needs 4 bits So

Total Number of Subnet = 2^4 = 16

Here we have 16384 hosts divided into 16 subnets each having 1024 hosts .

This is how we can solve each part according to given IP

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