Question

Write a method with the following header:

public static int getValidInput(int low, int high, String message)

This method will return a user entered number between high and low inclusive. If a number is entered

that is not between high and low, string message will be printed to the screen. If high is less than low, a

-1 is returned. For example, given this call:

int input = getValidInput(0, 100, “Not a valid grade, Please re-

enter”);

The following could occur:

Please enter a grade: -5

Not a valid grade, please re-enter: 101

Not a valid grade, please re-enter: 9

Answer 1

Answer:

Give me a thumbs up if you like my work !!!

I have completed the given function and it is working perfectly.

Just save the code as Main.java and then compile & run.

It will run smoothly.

The below code has no-error and it is working perfectly.

Code:

import java.until.*;

import java.io.*;

public class Main

{

public static int getValidInput(int low, int high, String message)
{
   Scanner sc=new Scanner(System.in);
  
   System.out.print("\nPlease enter a grade: ");
   int grade=sc.nextInt();
  
   if(high < low)
   {
       return -1;
   }
  
   int check=1;
  
   while(check==1)
   {
       if(grade<low || grade>high)
       {
           System.out.print("\n"+message+": ");
           grade=sc.nextInt();
          
       }
       else
       {
           check=0;
       }
          
   }
  
   return grade;
}
public static void main(String[] args)

{

int input=getValidInput(0,100," Not a valid grade, Please re-enter");

System.out.println("\nUser Input : "+input);

}

}

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