Question

In Python

def main():

c = 10

print("Welcome to Roderick's Chikkin and Gravy")

e = False

while not e:

x = input("Would you like some chikkin?")

if x == "Y" or x == "y":

c = f(c)

else:

e = True

if c == 0:

e = True

print("I hope you enjoyed your chikkin!")

def f(c):

if c > 0:

print("Got you some chikkin! Enjoy")

return c-1

else:

print("No chikkin left. Sorry")

return 0

main()

For practice with lists, create a Python repl that does the following: A user will type in 10 numbers. It then calculates and outputs the standard deviation (SD) of those numbers. The formula to use for the SD is found through the following mini-algorithm:

1. Find the average of the values.

2. Find the sum of the square of the difference between each item you read in and the average. So, if I only have 3 inputs 1,2,3, the average is 2 so the sum of the square of the differences is: (2-1)^2 + (2-2)^2 + (2- 3)^2 = 2 (in this example).

3. Divide the value in the previous step by 9 (for 10 numbers).

4. Take the square root of the value from the previous step.

Answer 1

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Solution :-

python code :-

lst = []   
# number of elemetns as input 
n = 10
print("enter the numbers :- ");  
for i in range(0, n): 
    temp = int(input()) 
    lst.append(temp)

# find average for list
mean = sum(lst)/len(lst)

# find variance for list
variance = sum([((x - mean) ** 2) for x in lst])

variance = variance/(n-1)

# take square root of variance for std deviation
stdDev = variance ** 0.5

print("standard deviation = " , stdDev)

Sample input /Output :-

enter the numbers :-
23
45
67
1
34
56
8
97
23
26
standard deviation = 29.00957696271277