Question

Implement function swap that takes a 2D list (a list of list of integers) and modifies it in-place by swapping the first element in each row with the last element in that row. The return value is None. You may not use slicing. You maynot use any list method like append, insert, etc. Modification must be in-place, you may not move the list itself or any of its sublists to a new memory location.

Examples:

reverse([[1,2,3],[4,5,6]])        ->    [[3,2,1],[6,5,4]]

reverse([[1,2,3,4],[5,6,7,8]])    ->    [[4,2,3,1],[8,6,7,5]]

True

False

In python please

Answer 1

Program Code Screenshot:

Sample output:

The screenshots are attached below for reference.

Please follow them for proper indentation and output.

Program to copy:

def swap(l):
for i in range(len(l)):
l[i][0],l[i][-1]=l[i][-1],l[i][0]#swap the first and last elements in that row
print(l)#print list after swapping
  
swap([[1,2,3],[4,5,6]])#call the function
swap([[1,2,3,4],[5,6,7,8]])

Note:

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