Question

What is the value of n and counter when the code below is executed?

n = 256; 
counter = 1; 
while n ~= 1 
 if rem(counter,2) == 0 

 n = n/2; 

 else 

 n = n/4; 

 end 
counter = counter + 1 ;
end

a.

n=1;

counter = 6

b.

n=5;

counter = 6;

c.

n=6;

counter = 256;

d.

n=256

counter = 6

e.

n=128;

counter=64;

Answer 1

counter = 1
n = 256

while 256 != 1
   1%2 =1, so
       n = n/4 = 64
       counter = 2
   2%2 = 0
       n = n/2 = 32
       counter = 3
   3%2 = 1
       n = n/4 = 8
       counter = 4
   4%2 = 0
       n = n/2 = 4
       counter = 5
   5%2 = 1
       n = n/4 = 1
       counter = 6

breaks the loop because condition fails for n is 1

So, n = 1
counter = 6

Answer : A