Some microprocessors are designed to have adjustable voltage, and reduction in voltage may cause a reduction in frequency. What is power reduction if voltage is reduced by 15% and frequency is reduced by 14%
Since the capacitance is unchanged, energy is the ratio of the voltages :
Energynew/Energyold = (voltage * ( 1 - 15%) )2 / voltage2
= (voltage * ( 1 - (15/100) ) )2 / voltage2
= (voltage * ( 1 - 0.15 ) )2 / voltage2
= (voltage * 0.85 )2 / voltage2
= 0.852
= 0.7225
thereby reducing energy to about 72.25% of the original. For power, we add the ratio of the frequencies
Powernew/Powerold = (Energynew/Energyold) * ( (Frequency switched * ( 1 - 14%) ) / Frequency switched )
= 0.7225 * ( (Frequency switched * ( 1 - (14/100)) ) / Frequency switched )
= 0.7225 * ( (Frequency switched * ( 1 - 0.14) ) / Frequency switched )
= 0.7225 * ( (Frequency switched * 0.86 ) / Frequency switched )
= 0.7225 * 0.86
= 0.62135
Therefore, the power reduction is about 62.14% of the original.
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