Question

void foo() { uint8_t a=2; uint8_t b[]={b0, b1, b2}; // They are the last three digits of your A# uint8_t* c=b; uint8_t* d=&a; }

address	value	variable
0x10C0		d
0x10C1
0x10C2		c
0x10C3
0x10C4		b
0x10C5
0x10C6
0x10C7		a

Assume the variables are arranged in data memory as in the table below. Put the values of the variables in the table.

Answer 1

SOLUTION-

Address	Value	Variable
0x10C0	0xC7	d
0x10C1	0x10
0x10C2	0xC4	c
0x10C3	0x10
0x10C4	b0	b
0x10C5	b1
0x10C6	b2
0x10C7	2	a

Note: I am using little endian format here. that's why (0xC4, 0x10) and (0xc7, 0x10) are stored in that order for c and d.

If it was big endian it would be stored in a different order.

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