Question

What is wrong with the following code segment, assumming it compiles correctly?

char *a = "Hello";

char *b = " Mom";

while( *b != '\0' ) {

*a = *b;

a++;

b++;

}

Answer 1

If your code compiles correctly then it is your logical error.

Here you can not write *a = *b like this as normal variable.

As you are assigning a value of pointer b to pointer a you must write like *a == *b;

*a = *b will give you segmentation fault.

while *a == *b works correctlly.