Question

Register	Value
$9	0xA136
$10	0x1234A136
$11	0x5555
$12	0x70000974
$13	7 (decmial)
$14	0x9AB

Give the result of the following instruction. Assume the initial values for the register above. Give the answer in hexadecimal using the 0x notation.

or $9, $10, $11

$9 =

Answer 1

The Given Instruction is

or $9, $10, $11

This means perform OR operation bit by bit between registers $10 and $11 and store the result in $9

We Know How OR operation behaves .

OR operation between two bits is 1 when at-least one bit is 1 otherwise output is 0

So To do OR bit by bit first lets write hexadecimal values into binary

We have $10=  0x1234A136 = 10010001101001010000100110110

And $11= 0x5555 = 101010101010101

Now Do OR Between Them Bit by Bits . To match length of both extend value of $11 by adding 0's on left of MSB .

Result is : 10010001101001111010101110111

Now Represent in Hex we get = 0x 1234F577

Hence Value Store in $9 = 0x 1234F577

This is how we can do OR operation between two hex numbers

Thank You

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