Question

Calculate Using Maltab.

The displacement of the oscillating spring can be described
by:

x = A*cos(ω*t)

where:

x = displacement at time t, +ve means upward -ve means
downwards

A = maximum displacement,

ω = angular frequency in radians per second, and

t = time in seconds

If the maximum displacement A = 4 cm and the angular frequency
is 0.6 radians per second.

What is the shortest time at which the displacement is equal to 2
cm (upwards)?

a)1.745

b) 1.111

c) 3.492

d) 6.984

***Explain the steps and process and how you calculated
the correct answer.**

Answer #1

ANSWER OPTION A

x = Acos(wt)

x/A = cos(wt)

wt = cos^{-1}(x/a)

put values,

wt = cos^{-1}(0.5)

wt = pi/3

t = pi/(3*w)

t = 1.745s ANS

MATLAB CODE:

x = 2;

A = 4;

w = 0.6;

%acos function to find cos inverse, using formula of t

t = acos(x/A)/w;

CODE SNIPPET:

WORKSPACE OUTPUT:

As we can see, t = 1.745 s.

Upvote if you liked the answer.

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