Consider IEEE standard single-precision floating-point format. What is the distance between the largest value and the 2nd largest value?
Dear Student I understand your problem and can say That his question is really interesting.Please you through the information given below you will surely get the answer.
A signed 32-cycle whole number variable has a most extreme estimation of 231 − 1 = 2,147,483,647, while an IEEE 754 32-bit base-2 skimming point variable has a greatest estimation of (2 − 2^23) × 2^127 ≈ 3.4028235 × 1038.
This is the largest mentioned value to be true now lets move ahead to the second last largest value and the difference of those two values is our answer.
Go through the interpretation of the value (2 − 2^23) × 2^126 and if you find this difference that is your answer.
I hope you have gone through the idea follow the steps and just put those values in your calculator and boom you get your answer.
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