Question

Given the following function declaration: int myFunction (int& myValue); Which of the following has a legal...

Given the following function declaration: int myFunction (int& myValue); Which of the following has a legal call to the function?

a.cout << myFunction(2);

b.cout << myFunction (4);

c.cout << myFunction ( var); // var is a variable of type int

d.int result = myFunction(3.5);

e.All of the above.

Homework Answers

Answer #1

Question:
Given the following function declaration: int myFunction (int& myValue); Which of the following has a legal call to the function?

Ans: cout << myFunction ( var); // var is a variable of type int

We can see that the function myFunction has a parameter is a reference of argument(simply we can say it as Address of the variable). So in order to call the function, we need a variable that holds a value. so that It can take the address of the variable, modify the value of the variable using that address.

So It is necessary that the argument should be a variable and specifically for this function it should be an int type because the function is accepting a parameter which is int reference. So all the 3 options which are wrong are:
cout << myFunction(2);
cout << myFunction (4);
int result = myFunction(3.5);

The correct way is to do this:
int var=2;
cout << myFunction (var);

Please find the compiled program of the code as well the output for your reference;

Output:


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